PA.11B, SEC 2, gen sqr seq (50)

Hint

An nth-term rule gives every number in the list.

n always starts at 1 and goes 2, 3, 4, … one step at a time.

The power 2 on n means you square (multiply by itself) the position each time.

Then you add or subtract the constant that follows.

Example: a_n = n² + 5.

Put n = 1 → (1)² + 5 = 6.

Put n = 2 → (2)² + 5 = 9.

So the list starts 6, 9, … just keep swapping in bigger n’s.

Still stuck? type LN.11 to review further.

Hint

No worries.

Solving for n when you know the term value in a quadratic nth-term rule (one with n squared) needs four tidy moves.

1) Substitute the given term value into the rule so n is the only unknown.

2) Add or subtract to move the constant (number on its own) across.

3) Divide by the coefficient (the number multiplying n²) to isolate n².

4) Square-root both sides and pick the positive answer because sequence positions are positive whole numbers.

Hint

No worries.

Solving for n when you know the term value in a quadratic nth-term rule (one with n squared) needs four tidy moves.

1) Substitute the given term value into the rule so n is the only unknown.

2) Add or subtract to move the constant (number on its own) across.

3) Divide by the coefficient (the number multiplying n²) to isolate n².

4) Square-root both sides and pick the positive answer because sequence positions are positive whole numbers.

Hint

An nth-term rule gives every number in the list.

n always starts at 1 and goes 2, 3, 4, … one step at a time.

The power 2 on n means you square (multiply by itself) the position each time.

Then you add or subtract the constant that follows.

Example: a_n = n² + 5.

Put n = 1 → (1)² + 5 = 6.

Put n = 2 → (2)² + 5 = 9.

So the list starts 6, 9, … just keep swapping in bigger n’s.

Still stuck? type LN.11 to review further.

Hint

No worries.

Solving for n when you know the term value in a quadratic nth-term rule (one with n squared) needs four tidy moves.

1) Substitute the given term value into the rule so n is the only unknown.

2) Add or subtract to move the constant (number on its own) across.

3) Divide by the coefficient (the number multiplying n²) to isolate n².

4) Square-root both sides and pick the positive answer because sequence positions are positive whole numbers.

Hint

No worries.

Solving for n when you know the term value in a quadratic nth-term rule (one with n squared) needs four tidy moves.

1) Substitute the given term value into the rule so n is the only unknown.

2) Add or subtract to move the constant (number on its own) across.

3) Divide by the coefficient (the number multiplying n²) to isolate n².

4) Square-root both sides and pick the positive answer because sequence positions are positive whole numbers.

Hint

An nth-term rule gives every number in the list.

n always starts at 1 and goes 2, 3, 4, … one step at a time.

The power 2 on n means you square (multiply by itself) the position each time.

Then you add or subtract the constant that follows.

Example: a_n = n² + 5.

Put n = 1 → (1)² + 5 = 6.

Put n = 2 → (2)² + 5 = 9.

So the list starts 6, 9, … just keep swapping in bigger n’s.

Still stuck? type LN.11 to review further.

Hint

No worries.

Solving for n when you know the term value in a quadratic nth-term rule (one with n squared) needs four tidy moves.

1) Substitute the given term value into the rule so n is the only unknown.

2) Add or subtract to move the constant (number on its own) across.

3) Divide by the coefficient (the number multiplying n²) to isolate n².

4) Square-root both sides and pick the positive answer because sequence positions are positive whole numbers.

Hint

No worries.

Solving for n when you know the term value in a quadratic nth-term rule (one with n squared) needs four tidy moves.

1) Substitute the given term value into the rule so n is the only unknown.

2) Add or subtract to move the constant (number on its own) across.

3) Divide by the coefficient (the number multiplying n²) to isolate n².

4) Square-root both sides and pick the positive answer because sequence positions are positive whole numbers.

Hint

An nth-term rule gives every number in the list.

n always starts at 1 and goes 2, 3, 4, … one step at a time.

The power 2 on n means you square (multiply by itself) the position each time.

Then you add or subtract the constant that follows.

Example: a_n = n² + 5.

Put n = 1 → (1)² + 5 = 6.

Put n = 2 → (2)² + 5 = 9.

So the list starts 6, 9, … just keep swapping in bigger n’s.

Still stuck? type LN.11 to review further.

Hint

No worries.

Solving for n when you know the term value in a quadratic nth-term rule (one with n squared) needs four tidy moves.

1) Substitute the given term value into the rule so n is the only unknown.

2) Add or subtract to move the constant (number on its own) across.

3) Divide by the coefficient (the number multiplying n²) to isolate n².

4) Square-root both sides and pick the positive answer because sequence positions are positive whole numbers.

Hint

No worries.

Solving for n when you know the term value in a quadratic nth-term rule (one with n squared) needs four tidy moves.

1) Substitute the given term value into the rule so n is the only unknown.

2) Add or subtract to move the constant (number on its own) across.

3) Divide by the coefficient (the number multiplying n²) to isolate n².

4) Square-root both sides and pick the positive answer because sequence positions are positive whole numbers.

Hint

An nth-term rule gives every number in the list.

n always starts at 1 and goes 2, 3, 4, … one step at a time.

The power 2 on n means you square (multiply by itself) the position each time.

Then you add or subtract the constant that follows.

Example: a_n = n² + 5.

Put n = 1 → (1)² + 5 = 6.

Put n = 2 → (2)² + 5 = 9.

So the list starts 6, 9, … just keep swapping in bigger n’s.

Still stuck? type LN.11 to review further.

Hint

An nth-term rule gives every number in the list.

n always starts at 1 and goes 2, 3, 4, … one step at a time.

The power 2 on n means you square (multiply by itself) the position each time.

Then you add or subtract the constant that follows.

Example: a_n = n² + 5.

Put n = 1 → (1)² + 5 = 6.

Put n = 2 → (2)² + 5 = 9.

So the list starts 6, 9, … just keep swapping in bigger n’s.

Still stuck? type LN.11 to review further.

Hint

No worries.

Solving for n when you know the term value in a quadratic nth-term rule (one with n squared) needs four tidy moves.

1) Substitute the given term value into the rule so n is the only unknown.

2) Add or subtract to move the constant (number on its own) across.

3) Divide by the coefficient (the number multiplying n²) to isolate n².

4) Square-root both sides and pick the positive answer because sequence positions are positive whole numbers.

Hint

No worries.

Solving for n when you know the term value in a quadratic nth-term rule (one with n squared) needs four tidy moves.

1) Substitute the given term value into the rule so n is the only unknown.

2) Add or subtract to move the constant (number on its own) across.

3) Divide by the coefficient (the number multiplying n²) to isolate n².

4) Square-root both sides and pick the positive answer because sequence positions are positive whole numbers.

Hint

An nth-term rule gives every number in the list.

n always starts at 1 and goes 2, 3, 4, … one step at a time.

The power 2 on n means you square (multiply by itself) the position each time.

Then you add or subtract the constant that follows.

Example: a_n = n² + 5.

Put n = 1 → (1)² + 5 = 6.

Put n = 2 → (2)² + 5 = 9.

So the list starts 6, 9, … just keep swapping in bigger n’s.

Still stuck? type LN.11 to review further.

Hint

An nth-term rule gives every number in the list.

n always starts at 1 and goes 2, 3, 4, … one step at a time.

The power 2 on n means you square (multiply by itself) the position each time.

Then you add or subtract the constant that follows.

Example: a_n = n² + 5.

Put n = 1 → (1)² + 5 = 6.

Put n = 2 → (2)² + 5 = 9.

So the list starts 6, 9, … just keep swapping in bigger n’s.

Still stuck? type LN.11 to review further.

Hint

No worries.

Solving for n when you know the term value in a quadratic nth-term rule (one with n squared) needs four tidy moves.

1) Substitute the given term value into the rule so n is the only unknown.

2) Add or subtract to move the constant (number on its own) across.

3) Divide by the coefficient (the number multiplying n²) to isolate n².

4) Square-root both sides and pick the positive answer because sequence positions are positive whole numbers.

Hint

No worries.

Solving for n when you know the term value in a quadratic nth-term rule (one with n squared) needs four tidy moves.

1) Substitute the given term value into the rule so n is the only unknown.

2) Add or subtract to move the constant (number on its own) across.

3) Divide by the coefficient (the number multiplying n²) to isolate n².

4) Square-root both sides and pick the positive answer because sequence positions are positive whole numbers.

Hint

An nth-term rule gives every number in the list.

n always starts at 1 and goes 2, 3, 4, … one step at a time.

The power 2 on n means you square (multiply by itself) the position each time.

Then you add or subtract the constant that follows.

Example: a_n = n² + 5.

Put n = 1 → (1)² + 5 = 6.

Put n = 2 → (2)² + 5 = 9.

So the list starts 6, 9, … just keep swapping in bigger n’s.

Still stuck? type LN.11 to review further.

Hint

An nth-term rule gives every number in the list.

n always starts at 1 and goes 2, 3, 4, … one step at a time.

The power 2 on n means you square (multiply by itself) the position each time.

Then you add or subtract the constant that follows.

Example: a_n = n² + 5.

Put n = 1 → (1)² + 5 = 6.

Put n = 2 → (2)² + 5 = 9.

So the list starts 6, 9, … just keep swapping in bigger n’s.

Still stuck? type LN.11 to review further.

Hint

No worries.

Solving for n when you know the term value in a quadratic nth-term rule (one with n squared) needs four tidy moves.

1) Substitute the given term value into the rule so n is the only unknown.

2) Add or subtract to move the constant (number on its own) across.

3) Divide by the coefficient (the number multiplying n²) to isolate n².

4) Square-root both sides and pick the positive answer because sequence positions are positive whole numbers.

Hint

An nth-term rule gives every number in the list.

n always starts at 1 and goes 2, 3, 4, … one step at a time.

The power 2 on n means you square (multiply by itself) the position each time.

Then you add or subtract the constant that follows.

Example: a_n = n² + 5.

Put n = 1 → (1)² + 5 = 6.

Put n = 2 → (2)² + 5 = 9.

So the list starts 6, 9, … just keep swapping in bigger n’s.

Still stuck? type LN.11 to review further.

Hint

An nth-term rule gives every number in the list.

n always starts at 1 and goes 2, 3, 4, … one step at a time.

The power 2 on n means you square (multiply by itself) the position each time.

Then you add or subtract the constant that follows.

Example: a_n = n² + 5.

Put n = 1 → (1)² + 5 = 6.

Put n = 2 → (2)² + 5 = 9.

So the list starts 6, 9, … just keep swapping in bigger n’s.

Still stuck? type LN.11 to review further.

Hint

No worries.

Solving for n when you know the term value in a quadratic nth-term rule (one with n squared) needs four tidy moves.

1) Substitute the given term value into the rule so n is the only unknown.

2) Add or subtract to move the constant (number on its own) across.

3) Divide by the coefficient (the number multiplying n²) to isolate n².

4) Square-root both sides and pick the positive answer because sequence positions are positive whole numbers.

Hint

An nth-term rule gives every number in the list.

n always starts at 1 and goes 2, 3, 4, … one step at a time.

The power 2 on n means you square (multiply by itself) the position each time.

Then you add or subtract the constant that follows.

Example: a_n = n² + 5.

Put n = 1 → (1)² + 5 = 6.

Put n = 2 → (2)² + 5 = 9.

So the list starts 6, 9, … just keep swapping in bigger n’s.

Still stuck? type LN.11 to review further.

Hint

An nth-term rule gives every number in the list.

n always starts at 1 and goes 2, 3, 4, … one step at a time.

The power 2 on n means you square (multiply by itself) the position each time.

Then you add or subtract the constant that follows.

Example: a_n = n² + 5.

Put n = 1 → (1)² + 5 = 6.

Put n = 2 → (2)² + 5 = 9.

So the list starts 6, 9, … just keep swapping in bigger n’s.

Still stuck? type LN.11 to review further.

Hint

No worries.

Solving for n when you know the term value in a quadratic nth-term rule (one with n squared) needs four tidy moves.

1) Substitute the given term value into the rule so n is the only unknown.

2) Add or subtract to move the constant (number on its own) across.

3) Divide by the coefficient (the number multiplying n²) to isolate n².

4) Square-root both sides and pick the positive answer because sequence positions are positive whole numbers.

Hint

An nth-term rule gives every number in the list.

n always starts at 1 and goes 2, 3, 4, … one step at a time.

The power 2 on n means you square (multiply by itself) the position each time.

Then you add or subtract the constant that follows.

Example: a_n = n² + 5.

Put n = 1 → (1)² + 5 = 6.

Put n = 2 → (2)² + 5 = 9.

So the list starts 6, 9, … just keep swapping in bigger n’s.

Still stuck? type LN.11 to review further.

Hint

An nth-term rule gives every number in the list.

n always starts at 1 and goes 2, 3, 4, … one step at a time.

The power 2 on n means you square (multiply by itself) the position each time.

Then you add or subtract the constant that follows.

Example: a_n = n² + 5.

Put n = 1 → (1)² + 5 = 6.

Put n = 2 → (2)² + 5 = 9.

So the list starts 6, 9, … just keep swapping in bigger n’s.

Still stuck? type LN.11 to review further.

Hint

No worries.

Solving for n when you know the term value in a quadratic nth-term rule (one with n squared) needs four tidy moves.

1) Substitute the given term value into the rule so n is the only unknown.

2) Add or subtract to move the constant (number on its own) across.

3) Divide by the coefficient (the number multiplying n²) to isolate n².

4) Square-root both sides and pick the positive answer because sequence positions are positive whole numbers.

Hint

An nth-term rule gives every number in the list.

n always starts at 1 and goes 2, 3, 4, … one step at a time.

The power 2 on n means you square (multiply by itself) the position each time.

Then you add or subtract the constant that follows.

Example: a_n = n² + 5.

Put n = 1 → (1)² + 5 = 6.

Put n = 2 → (2)² + 5 = 9.

So the list starts 6, 9, … just keep swapping in bigger n’s.

Still stuck? type LN.11 to review further.

Hint

An nth-term rule gives every number in the list.

n always starts at 1 and goes 2, 3, 4, … one step at a time.

The power 2 on n means you square (multiply by itself) the position each time.

Then you add or subtract the constant that follows.

Example: a_n = n² + 5.

Put n = 1 → (1)² + 5 = 6.

Put n = 2 → (2)² + 5 = 9.

So the list starts 6, 9, … just keep swapping in bigger n’s.

Still stuck? type LN.11 to review further.

Hint

No worries.

Solving for n when you know the term value in a quadratic nth-term rule (one with n squared) needs four tidy moves.

1) Substitute the given term value into the rule so n is the only unknown.

2) Add or subtract to move the constant (number on its own) across.

3) Divide by the coefficient (the number multiplying n²) to isolate n².

4) Square-root both sides and pick the positive answer because sequence positions are positive whole numbers.

Hint

An nth-term rule gives every number in the list.

n always starts at 1 and goes 2, 3, 4, … one step at a time.

The power 2 on n means you square (multiply by itself) the position each time.

Then you add or subtract the constant that follows.

Example: a_n = n² + 5.

Put n = 1 → (1)² + 5 = 6.

Put n = 2 → (2)² + 5 = 9.

So the list starts 6, 9, … just keep swapping in bigger n’s.

Still stuck? type LN.11 to review further.

Hint

An nth-term rule gives every number in the list.

n always starts at 1 and goes 2, 3, 4, … one step at a time.

The power 2 on n means you square (multiply by itself) the position each time.

Then you add or subtract the constant that follows.

Example: a_n = n² + 5.

Put n = 1 → (1)² + 5 = 6.

Put n = 2 → (2)² + 5 = 9.

So the list starts 6, 9, … just keep swapping in bigger n’s.

Still stuck? type LN.11 to review further.

Hint

No worries.

Solving for n when you know the term value in a quadratic nth-term rule (one with n squared) needs four tidy moves.

1) Substitute the given term value into the rule so n is the only unknown.

2) Add or subtract to move the constant (number on its own) across.

3) Divide by the coefficient (the number multiplying n²) to isolate n².

4) Square-root both sides and pick the positive answer because sequence positions are positive whole numbers.

Hint

An nth-term rule gives every number in the list.

n always starts at 1 and goes 2, 3, 4, … one step at a time.

The power 2 on n means you square (multiply by itself) the position each time.

Then you add or subtract the constant that follows.

Example: a_n = n² + 5.

Put n = 1 → (1)² + 5 = 6.

Put n = 2 → (2)² + 5 = 9.

So the list starts 6, 9, … just keep swapping in bigger n’s.

Still stuck? type LN.11 to review further.

Hint

An nth-term rule gives every number in the list.

n always starts at 1 and goes 2, 3, 4, … one step at a time.

The power 2 on n means you square (multiply by itself) the position each time.

Then you add or subtract the constant that follows.

Example: a_n = n² + 5.

Put n = 1 → (1)² + 5 = 6.

Put n = 2 → (2)² + 5 = 9.

So the list starts 6, 9, … just keep swapping in bigger n’s.

Still stuck? type LN.11 to review further.

Hint

No worries.

Solving for n when you know the term value in a quadratic nth-term rule (one with n squared) needs four tidy moves.

1) Substitute the given term value into the rule so n is the only unknown.

2) Add or subtract to move the constant (number on its own) across.

3) Divide by the coefficient (the number multiplying n²) to isolate n².

4) Square-root both sides and pick the positive answer because sequence positions are positive whole numbers.

Hint

An nth-term rule gives every number in the list.

n always starts at 1 and goes 2, 3, 4, … one step at a time.

The power 2 on n means you square (multiply by itself) the position each time.

Then you add or subtract the constant that follows.

Example: a_n = n² + 5.

Put n = 1 → (1)² + 5 = 6.

Put n = 2 → (2)² + 5 = 9.

So the list starts 6, 9, … just keep swapping in bigger n’s.

Still stuck? type LN.11 to review further.

Hint

No worries.

Solving for n when you know the term value in a quadratic nth-term rule (one with n squared) needs four tidy moves.

1) Substitute the given term value into the rule so n is the only unknown.

2) Add or subtract to move the constant (number on its own) across.

3) Divide by the coefficient (the number multiplying n²) to isolate n².

4) Square-root both sides and pick the positive answer because sequence positions are positive whole numbers.

Hint

No worries.

Solving for n when you know the term value in a quadratic nth-term rule (one with n squared) needs four tidy moves.

1) Substitute the given term value into the rule so n is the only unknown.

2) Add or subtract to move the constant (number on its own) across.

3) Divide by the coefficient (the number multiplying n²) to isolate n².

4) Square-root both sides and pick the positive answer because sequence positions are positive whole numbers.

Hint

An nth-term rule gives every number in the list.

n always starts at 1 and goes 2, 3, 4, … one step at a time.

The power 2 on n means you square (multiply by itself) the position each time.

Then you add or subtract the constant that follows.

Example: a_n = n² + 5.

Put n = 1 → (1)² + 5 = 6.

Put n = 2 → (2)² + 5 = 9.

So the list starts 6, 9, … just keep swapping in bigger n’s.

Still stuck? type LN.11 to review further.

Hint

No worries.

Solving for n when you know the term value in a quadratic nth-term rule (one with n squared) needs four tidy moves.

1) Substitute the given term value into the rule so n is the only unknown.

2) Add or subtract to move the constant (number on its own) across.

3) Divide by the coefficient (the number multiplying n²) to isolate n².

4) Square-root both sides and pick the positive answer because sequence positions are positive whole numbers.

Hint

No worries.

Solving for n when you know the term value in a quadratic nth-term rule (one with n squared) needs four tidy moves.

1) Substitute the given term value into the rule so n is the only unknown.

2) Add or subtract to move the constant (number on its own) across.

3) Divide by the coefficient (the number multiplying n²) to isolate n².

4) Square-root both sides and pick the positive answer because sequence positions are positive whole numbers.

Hint

An nth-term rule gives every number in the list.

n always starts at 1 and goes 2, 3, 4, … one step at a time.

The power 2 on n means you square (multiply by itself) the position each time.

Then you add or subtract the constant that follows.

Example: a_n = n² + 5.

Put n = 1 → (1)² + 5 = 6.

Put n = 2 → (2)² + 5 = 9.

So the list starts 6, 9, … just keep swapping in bigger n’s.

Still stuck? type LN.11 to review further.

Hint

No worries.

Solving for n when you know the term value in a quadratic nth-term rule (one with n squared) needs four tidy moves.

1) Substitute the given term value into the rule so n is the only unknown.

2) Add or subtract to move the constant (number on its own) across.

3) Divide by the coefficient (the number multiplying n²) to isolate n².

4) Square-root both sides and pick the positive answer because sequence positions are positive whole numbers.

Hint

No worries.

Solving for n when you know the term value in a quadratic nth-term rule (one with n squared) needs four tidy moves.

1) Substitute the given term value into the rule so n is the only unknown.

2) Add or subtract to move the constant (number on its own) across.

3) Divide by the coefficient (the number multiplying n²) to isolate n².

4) Square-root both sides and pick the positive answer because sequence positions are positive whole numbers.