PA.2B, SEC 3, Factorising 3 (36)
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Question 1 of 36
1. Question
Topic: Factorising Quadratic Expressions.
Please have pen and paper handy to show workings out. 📝
Factorize:
-
⌨️ Type your answer without spaces.
CorrectIncorrectHint
Hint: Finding the Right Numbers
To factorize a quadratic like x² + 5x + 6, you need to find two numbers that multiply to give the end coefficient (6) and add to give the x coefficient (5). 💡
Step 1: List pairs of numbers that multiply to 6:
1 × 6 = 6
2 × 3 = 6
-1 × -6 = 6
-2 × -3 = 6Step 2: Check which pair adds up to 5 (the x coefficient):
1 + 6 = 7 (too high)
2 + 3 = 5 (perfect!)The two numbers you found are 2 and 3. These are the numbers that go into the brackets: (x + 2)(x + 3). If the correct pair were negative, you would still use them, like (x – 2)(x – 3). 💡
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-
Question 2 of 36
2. Question
Topic: Factorising Quadratic Expressions.
Please have pen and paper handy to show workings out. 📝
Factorize:
-
⌨️ Type your answer without spaces.
CorrectIncorrectHint
Hint: Finding the Right Numbers When x Coefficient is 0
When the x coefficient is 0, like in x² – 9, write it as x² + 0x – 9 to see it clearly. You need two numbers that multiply to give the end coefficient (-9) and add to give the x coefficient (0). 💡
Step 1: List pairs of numbers that multiply to -9:
1 × -9 = -9
-1 × 9 = -9
3 × -3 = -9Step 2: Check which pair adds up to 0 (the x coefficient):
1 – 9 = -8 (too low)
-1 + 9 = 8 (too high)
3 – 3 = 0 (perfect!)The two numbers you found are 3 and -3. These are the numbers that go into the brackets: (x + 3)(x – 3). 💡
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-
Question 3 of 36
3. Question
Topic: Factorising Quadratic Expressions.
Please have pen and paper handy to show workings out. 📝
Factorize:
-
⌨️ Type your answer without spaces.
CorrectIncorrectHint
Hint: Finding the Right Numbers
To factorize a quadratic like x² + 5x + 6, you need to find two numbers that multiply to give the end coefficient (6) and add to give the x coefficient (5). 💡
Step 1: List pairs of numbers that multiply to 6:
1 × 6 = 6
2 × 3 = 6
-1 × -6 = 6
-2 × -3 = 6Step 2: Check which pair adds up to 5 (the x coefficient):
1 + 6 = 7 (too high)
2 + 3 = 5 (perfect!)The two numbers you found are 2 and 3. These are the numbers that go into the brackets: (x + 2)(x + 3). If the correct pair were negative, you would still use them, like (x – 2)(x – 3). 💡
-
-
Question 4 of 36
4. Question
Topic: Factorising Quadratic Expressions.
Please have pen and paper handy to show workings out. 📝
Factorize:
-
⌨️ Type your answer without spaces.
CorrectIncorrectHint
Hint: Finding the Right Numbers When x Coefficient is 0
When the x coefficient is 0, like in x² – 9, write it as x² + 0x – 9 to see it clearly. You need two numbers that multiply to give the end coefficient (-9) and add to give the x coefficient (0). 💡
Step 1: List pairs of numbers that multiply to -9:
1 × -9 = -9
-1 × 9 = -9
3 × -3 = -9Step 2: Check which pair adds up to 0 (the x coefficient):
1 – 9 = -8 (too low)
-1 + 9 = 8 (too high)
3 – 3 = 0 (perfect!)The two numbers you found are 3 and -3. These are the numbers that go into the brackets: (x + 3)(x – 3). 💡
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-
Question 5 of 36
5. Question
Topic: Factorising Quadratic Expressions.
Please have pen and paper handy to show workings out. 📝
Factorize:
-
⌨️ Type your answer without spaces.
CorrectIncorrectHint
Hint: Finding the Right Numbers
To factorize a quadratic like x² + 5x + 6, you need to find two numbers that multiply to give the end coefficient (6) and add to give the x coefficient (5). 💡
Step 1: List pairs of numbers that multiply to 6:
1 × 6 = 6
2 × 3 = 6
-1 × -6 = 6
-2 × -3 = 6Step 2: Check which pair adds up to 5 (the x coefficient):
1 + 6 = 7 (too high)
2 + 3 = 5 (perfect!)The two numbers you found are 2 and 3. These are the numbers that go into the brackets: (x + 2)(x + 3). If the correct pair were negative, you would still use them, like (x – 2)(x – 3). 💡
-
-
Question 6 of 36
6. Question
Topic: Factorising Quadratic Expressions.
Please have pen and paper handy to show workings out. 📝
Factorize:
-
⌨️ Type your answer without spaces.
CorrectIncorrectHint
Hint: Finding the Right Numbers When x Coefficient is 0
When the x coefficient is 0, like in x² – 9, write it as x² + 0x – 9 to see it clearly. You need two numbers that multiply to give the end coefficient (-9) and add to give the x coefficient (0). 💡
Step 1: List pairs of numbers that multiply to -9:
1 × -9 = -9
-1 × 9 = -9
3 × -3 = -9Step 2: Check which pair adds up to 0 (the x coefficient):
1 – 9 = -8 (too low)
-1 + 9 = 8 (too high)
3 – 3 = 0 (perfect!)The two numbers you found are 3 and -3. These are the numbers that go into the brackets: (x + 3)(x – 3). 💡
-
-
Question 7 of 36
7. Question
Topic: Factorising Quadratic Expressions.
Please have pen and paper handy to show workings out. 📝
Factorize:
-
⌨️ Type your answer without spaces.
CorrectIncorrectHint
Hint: Finding the Right Numbers
To factorize a quadratic like x² + 5x + 6, you need to find two numbers that multiply to give the end coefficient (6) and add to give the x coefficient (5). 💡
Step 1: List pairs of numbers that multiply to 6:
1 × 6 = 6
2 × 3 = 6
-1 × -6 = 6
-2 × -3 = 6Step 2: Check which pair adds up to 5 (the x coefficient):
1 + 6 = 7 (too high)
2 + 3 = 5 (perfect!)The two numbers you found are 2 and 3. These are the numbers that go into the brackets: (x + 2)(x + 3). If the correct pair were negative, you would still use them, like (x – 2)(x – 3). 💡
-
-
Question 8 of 36
8. Question
Topic: Factorising Quadratic Expressions.
Please have pen and paper handy to show workings out. 📝
Factorize:
-
⌨️ Type your answer without spaces.
CorrectIncorrectHint
Hint: Finding the Right Numbers When x Coefficient is 0
When the x coefficient is 0, like in x² – 9, write it as x² + 0x – 9 to see it clearly. You need two numbers that multiply to give the end coefficient (-9) and add to give the x coefficient (0). 💡
Step 1: List pairs of numbers that multiply to -9:
1 × -9 = -9
-1 × 9 = -9
3 × -3 = -9Step 2: Check which pair adds up to 0 (the x coefficient):
1 – 9 = -8 (too low)
-1 + 9 = 8 (too high)
3 – 3 = 0 (perfect!)The two numbers you found are 3 and -3. These are the numbers that go into the brackets: (x + 3)(x – 3). 💡
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-
Question 9 of 36
9. Question
Topic: Factorising Quadratic Expressions.
Please have pen and paper handy to show workings out. 📝
Factorize:
-
⌨️ Type your answer without spaces.
CorrectIncorrectHint
Hint: Finding the Right Numbers
To factorize a quadratic like x² + 5x + 6, you need to find two numbers that multiply to give the end coefficient (6) and add to give the x coefficient (5). 💡
Step 1: List pairs of numbers that multiply to 6:
1 × 6 = 6
2 × 3 = 6
-1 × -6 = 6
-2 × -3 = 6Step 2: Check which pair adds up to 5 (the x coefficient):
1 + 6 = 7 (too high)
2 + 3 = 5 (perfect!)The two numbers you found are 2 and 3. These are the numbers that go into the brackets: (x + 2)(x + 3). If the correct pair were negative, you would still use them, like (x – 2)(x – 3). 💡
-
-
Question 10 of 36
10. Question
Topic: Factorising Quadratic Expressions.
Please have pen and paper handy to show workings out. 📝
Factorize:
-
⌨️ Type your answer without spaces.
CorrectIncorrectHint
Hint: Finding the Right Numbers When x Coefficient is 0
When the x coefficient is 0, like in x² – 9, write it as x² + 0x – 9 to see it clearly. You need two numbers that multiply to give the end coefficient (-9) and add to give the x coefficient (0). 💡
Step 1: List pairs of numbers that multiply to -9:
1 × -9 = -9
-1 × 9 = -9
3 × -3 = -9Step 2: Check which pair adds up to 0 (the x coefficient):
1 – 9 = -8 (too low)
-1 + 9 = 8 (too high)
3 – 3 = 0 (perfect!)The two numbers you found are 3 and -3. These are the numbers that go into the brackets: (x + 3)(x – 3). 💡
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-
Question 11 of 36
11. Question
Topic: Factorising Quadratic Expressions.
Please have pen and paper handy to show workings out. 📝
Factorize:
-
⌨️ Type your answer without spaces.
CorrectIncorrectHint
Hint: Finding the Right Numbers
To factorize a quadratic like x² + 5x + 6, you need to find two numbers that multiply to give the end coefficient (6) and add to give the x coefficient (5). 💡
Step 1: List pairs of numbers that multiply to 6:
1 × 6 = 6
2 × 3 = 6
-1 × -6 = 6
-2 × -3 = 6Step 2: Check which pair adds up to 5 (the x coefficient):
1 + 6 = 7 (too high)
2 + 3 = 5 (perfect!)The two numbers you found are 2 and 3. These are the numbers that go into the brackets: (x + 2)(x + 3). If the correct pair were negative, you would still use them, like (x – 2)(x – 3). 💡
-
-
Question 12 of 36
12. Question
Topic: Factorising Quadratic Expressions.
Please have pen and paper handy to show workings out. 📝
Factorize:
-
⌨️ Type your answer without spaces.
CorrectIncorrectHint
Hint: Finding the Right Numbers When x Coefficient is 0
When the x coefficient is 0, like in x² – 9, write it as x² + 0x – 9 to see it clearly. You need two numbers that multiply to give the end coefficient (-9) and add to give the x coefficient (0). 💡
Step 1: List pairs of numbers that multiply to -9:
1 × -9 = -9
-1 × 9 = -9
3 × -3 = -9Step 2: Check which pair adds up to 0 (the x coefficient):
1 – 9 = -8 (too low)
-1 + 9 = 8 (too high)
3 – 3 = 0 (perfect!)The two numbers you found are 3 and -3. These are the numbers that go into the brackets: (x + 3)(x – 3). 💡
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-
Question 13 of 36
13. Question
Topic: Factorising Quadratic Expressions.
Please have pen and paper handy to show workings out. 📝
Factorize:
-
⌨️ Type your answer without spaces.
CorrectIncorrectHint
Hint: Finding the Right Numbers
To factorize a quadratic like x² + 5x + 6, you need to find two numbers that multiply to give the end coefficient (6) and add to give the x coefficient (5). 💡
Step 1: List pairs of numbers that multiply to 6:
1 × 6 = 6
2 × 3 = 6
-1 × -6 = 6
-2 × -3 = 6Step 2: Check which pair adds up to 5 (the x coefficient):
1 + 6 = 7 (too high)
2 + 3 = 5 (perfect!)The two numbers you found are 2 and 3. These are the numbers that go into the brackets: (x + 2)(x + 3). If the correct pair were negative, you would still use them, like (x – 2)(x – 3). 💡
-
-
Question 14 of 36
14. Question
Topic: Factorising Quadratic Expressions.
Please have pen and paper handy to show workings out. 📝
Factorize:
-
⌨️ Type your answer without spaces.
CorrectIncorrectHint
Hint: Finding the Right Numbers When x Coefficient is 0
When the x coefficient is 0, like in x² – 9, write it as x² + 0x – 9 to see it clearly. You need two numbers that multiply to give the end coefficient (-9) and add to give the x coefficient (0). 💡
Step 1: List pairs of numbers that multiply to -9:
1 × -9 = -9
-1 × 9 = -9
3 × -3 = -9Step 2: Check which pair adds up to 0 (the x coefficient):
1 – 9 = -8 (too low)
-1 + 9 = 8 (too high)
3 – 3 = 0 (perfect!)The two numbers you found are 3 and -3. These are the numbers that go into the brackets: (x + 3)(x – 3). 💡
-
-
Question 15 of 36
15. Question
Topic: Factorising Quadratic Expressions.
Please have pen and paper handy to show workings out. 📝
Factorize:
-
⌨️ Type your answer without spaces.
CorrectIncorrectHint
Hint: Finding the Right Numbers
To factorize a quadratic like x² + 5x + 6, you need to find two numbers that multiply to give the end coefficient (6) and add to give the x coefficient (5). 💡
Step 1: List pairs of numbers that multiply to 6:
1 × 6 = 6
2 × 3 = 6
-1 × -6 = 6
-2 × -3 = 6Step 2: Check which pair adds up to 5 (the x coefficient):
1 + 6 = 7 (too high)
2 + 3 = 5 (perfect!)The two numbers you found are 2 and 3. These are the numbers that go into the brackets: (x + 2)(x + 3). If the correct pair were negative, you would still use them, like (x – 2)(x – 3). 💡
-
-
Question 16 of 36
16. Question
Topic: Factorising Quadratic Expressions.
Please have pen and paper handy to show workings out. 📝
Factorize:
-
⌨️ Type your answer without spaces.
CorrectIncorrectHint
Hint: Finding the Right Numbers When x Coefficient is 0
When the x coefficient is 0, like in x² – 9, write it as x² + 0x – 9 to see it clearly. You need two numbers that multiply to give the end coefficient (-9) and add to give the x coefficient (0). 💡
Step 1: List pairs of numbers that multiply to -9:
1 × -9 = -9
-1 × 9 = -9
3 × -3 = -9Step 2: Check which pair adds up to 0 (the x coefficient):
1 – 9 = -8 (too low)
-1 + 9 = 8 (too high)
3 – 3 = 0 (perfect!)The two numbers you found are 3 and -3. These are the numbers that go into the brackets: (x + 3)(x – 3). 💡
-
-
Question 17 of 36
17. Question
Topic: Factorising Quadratic Expressions.
Please have pen and paper handy to show workings out. 📝
Factorize:
-
⌨️ Type your answer without spaces.
CorrectIncorrectHint
Hint: Finding the Right Numbers
To factorize a quadratic like x² + 5x + 6, you need to find two numbers that multiply to give the end coefficient (6) and add to give the x coefficient (5). 💡
Step 1: List pairs of numbers that multiply to 6:
1 × 6 = 6
2 × 3 = 6
-1 × -6 = 6
-2 × -3 = 6Step 2: Check which pair adds up to 5 (the x coefficient):
1 + 6 = 7 (too high)
2 + 3 = 5 (perfect!)The two numbers you found are 2 and 3. These are the numbers that go into the brackets: (x + 2)(x + 3). If the correct pair were negative, you would still use them, like (x – 2)(x – 3). 💡
-
-
Question 18 of 36
18. Question
Topic: Factorising Quadratic Expressions.
Please have pen and paper handy to show workings out. 📝
Factorize:
-
⌨️ Type your answer without spaces.
CorrectIncorrectHint
Hint: Finding the Right Numbers When x Coefficient is 0
When the x coefficient is 0, like in x² – 9, write it as x² + 0x – 9 to see it clearly. You need two numbers that multiply to give the end coefficient (-9) and add to give the x coefficient (0). 💡
Step 1: List pairs of numbers that multiply to -9:
1 × -9 = -9
-1 × 9 = -9
3 × -3 = -9Step 2: Check which pair adds up to 0 (the x coefficient):
1 – 9 = -8 (too low)
-1 + 9 = 8 (too high)
3 – 3 = 0 (perfect!)The two numbers you found are 3 and -3. These are the numbers that go into the brackets: (x + 3)(x – 3). 💡
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-
Question 19 of 36
19. Question
Topic: Factorising Quadratic Expressions.
Please have pen and paper handy to show workings out. 📝
Factorize:
-
⌨️ Type your answer without spaces.
CorrectIncorrectHint
Hint: Finding the Right Numbers
To factorize a quadratic like x² + 5x + 6, you need to find two numbers that multiply to give the end coefficient (6) and add to give the x coefficient (5). 💡
Step 1: List pairs of numbers that multiply to 6:
1 × 6 = 6
2 × 3 = 6
-1 × -6 = 6
-2 × -3 = 6Step 2: Check which pair adds up to 5 (the x coefficient):
1 + 6 = 7 (too high)
2 + 3 = 5 (perfect!)The two numbers you found are 2 and 3. These are the numbers that go into the brackets: (x + 2)(x + 3). If the correct pair were negative, you would still use them, like (x – 2)(x – 3). 💡
-
-
Question 20 of 36
20. Question
Topic: Factorising Quadratic Expressions.
Please have pen and paper handy to show workings out. 📝
Factorize:
-
⌨️ Type your answer without spaces.
CorrectIncorrectHint
Hint: Finding the Right Numbers When x Coefficient is 0
When the x coefficient is 0, like in x² – 9, write it as x² + 0x – 9 to see it clearly. You need two numbers that multiply to give the end coefficient (-9) and add to give the x coefficient (0). 💡
Step 1: List pairs of numbers that multiply to -9:
1 × -9 = -9
-1 × 9 = -9
3 × -3 = -9Step 2: Check which pair adds up to 0 (the x coefficient):
1 – 9 = -8 (too low)
-1 + 9 = 8 (too high)
3 – 3 = 0 (perfect!)The two numbers you found are 3 and -3. These are the numbers that go into the brackets: (x + 3)(x – 3). 💡
-
-
Question 21 of 36
21. Question
Topic: Factorising Quadratic Expressions.
Please have pen and paper handy to show workings out. 📝
Factorize:
-
⌨️ Type your answer without spaces.
CorrectIncorrectHint
Hint: Finding the Right Numbers
To factorize a quadratic like x² + 5x + 6, you need to find two numbers that multiply to give the end coefficient (6) and add to give the x coefficient (5). 💡
Step 1: List pairs of numbers that multiply to 6:
1 × 6 = 6
2 × 3 = 6
-1 × -6 = 6
-2 × -3 = 6Step 2: Check which pair adds up to 5 (the x coefficient):
1 + 6 = 7 (too high)
2 + 3 = 5 (perfect!)The two numbers you found are 2 and 3. These are the numbers that go into the brackets: (x + 2)(x + 3). If the correct pair were negative, you would still use them, like (x – 2)(x – 3). 💡
-
-
Question 22 of 36
22. Question
Topic: Factorising Quadratic Expressions.
Please have pen and paper handy to show workings out. 📝
Factorize:
-
⌨️ Type your answer without spaces.
CorrectIncorrectHint
Hint: Finding the Right Numbers
To factorize a quadratic like x² + 5x + 6, you need to find two numbers that multiply to give the end coefficient (6) and add to give the x coefficient (5). 💡
Step 1: List pairs of numbers that multiply to 6:
1 × 6 = 6
2 × 3 = 6
-1 × -6 = 6
-2 × -3 = 6Step 2: Check which pair adds up to 5 (the x coefficient):
1 + 6 = 7 (too high)
2 + 3 = 5 (perfect!)The two numbers you found are 2 and 3. These are the numbers that go into the brackets: (x + 2)(x + 3). If the correct pair were negative, you would still use them, like (x – 2)(x – 3). 💡
-
-
Question 23 of 36
23. Question
Topic: Factorising Quadratic Expressions.
Please have pen and paper handy to show workings out. 📝
Factorize:
-
⌨️ Type your answer without spaces.
CorrectIncorrectHint
Hint: Finding the Right Numbers When x Coefficient is 0
When the x coefficient is 0, like in x² – 9, write it as x² + 0x – 9 to see it clearly. You need two numbers that multiply to give the end coefficient (-9) and add to give the x coefficient (0). 💡
Step 1: List pairs of numbers that multiply to -9:
1 × -9 = -9
-1 × 9 = -9
3 × -3 = -9Step 2: Check which pair adds up to 0 (the x coefficient):
1 – 9 = -8 (too low)
-1 + 9 = 8 (too high)
3 – 3 = 0 (perfect!)The two numbers you found are 3 and -3. These are the numbers that go into the brackets: (x + 3)(x – 3). 💡
-
-
Question 24 of 36
24. Question
Topic: Factorising Quadratic Expressions.
Please have pen and paper handy to show workings out. 📝
Factorize:
-
⌨️ Type your answer without spaces.
CorrectIncorrectHint
Hint: Finding the Right Numbers
To factorize a quadratic like x² + 5x + 6, you need to find two numbers that multiply to give the end coefficient (6) and add to give the x coefficient (5). 💡
Step 1: List pairs of numbers that multiply to 6:
1 × 6 = 6
2 × 3 = 6
-1 × -6 = 6
-2 × -3 = 6Step 2: Check which pair adds up to 5 (the x coefficient):
1 + 6 = 7 (too high)
2 + 3 = 5 (perfect!)The two numbers you found are 2 and 3. These are the numbers that go into the brackets: (x + 2)(x + 3). If the correct pair were negative, you would still use them, like (x – 2)(x – 3). 💡
-
-
Question 25 of 36
25. Question
Topic: Factorising Quadratic Expressions.
Please have pen and paper handy to show workings out. 📝
Factorize:
-
⌨️ Type your answer without spaces.
CorrectIncorrectHint
Hint: Finding the Right Numbers
To factorize a quadratic like x² + 5x + 6, you need to find two numbers that multiply to give the end coefficient (6) and add to give the x coefficient (5). 💡
Step 1: List pairs of numbers that multiply to 6:
1 × 6 = 6
2 × 3 = 6
-1 × -6 = 6
-2 × -3 = 6Step 2: Check which pair adds up to 5 (the x coefficient):
1 + 6 = 7 (too high)
2 + 3 = 5 (perfect!)The two numbers you found are 2 and 3. These are the numbers that go into the brackets: (x + 2)(x + 3). If the correct pair were negative, you would still use them, like (x – 2)(x – 3). 💡
-
-
Question 26 of 36
26. Question
Topic: Factorising Quadratic Expressions.
Please have pen and paper handy to show workings out. 📝
Factorize:
-
⌨️ Type your answer without spaces.
CorrectIncorrectHint
Hint: Finding the Right Numbers When x Coefficient is 0
When the x coefficient is 0, like in x² – 9, write it as x² + 0x – 9 to see it clearly. You need two numbers that multiply to give the end coefficient (-9) and add to give the x coefficient (0). 💡
Step 1: List pairs of numbers that multiply to -9:
1 × -9 = -9
-1 × 9 = -9
3 × -3 = -9Step 2: Check which pair adds up to 0 (the x coefficient):
1 – 9 = -8 (too low)
-1 + 9 = 8 (too high)
3 – 3 = 0 (perfect!)The two numbers you found are 3 and -3. These are the numbers that go into the brackets: (x + 3)(x – 3). 💡
-
-
Question 27 of 36
27. Question
Topic: Factorising Quadratic Expressions.
Please have pen and paper handy to show workings out. 📝
Factorize:
-
⌨️ Type your answer without spaces.
CorrectIncorrectHint
Hint: Finding the Right Numbers
To factorize a quadratic like x² + 5x + 6, you need to find two numbers that multiply to give the end coefficient (6) and add to give the x coefficient (5). 💡
Step 1: List pairs of numbers that multiply to 6:
1 × 6 = 6
2 × 3 = 6
-1 × -6 = 6
-2 × -3 = 6Step 2: Check which pair adds up to 5 (the x coefficient):
1 + 6 = 7 (too high)
2 + 3 = 5 (perfect!)The two numbers you found are 2 and 3. These are the numbers that go into the brackets: (x + 2)(x + 3). If the correct pair were negative, you would still use them, like (x – 2)(x – 3). 💡
-
-
Question 28 of 36
28. Question
Topic: Factorising Quadratic Expressions.
Please have pen and paper handy to show workings out. 📝
Factorize:
-
⌨️ Type your answer without spaces.
CorrectIncorrectHint
Hint: Finding the Right Numbers When x Coefficient is 0
When the x coefficient is 0, like in x² – 9, write it as x² + 0x – 9 to see it clearly. You need two numbers that multiply to give the end coefficient (-9) and add to give the x coefficient (0). 💡
Step 1: List pairs of numbers that multiply to -9:
1 × -9 = -9
-1 × 9 = -9
3 × -3 = -9Step 2: Check which pair adds up to 0 (the x coefficient):
1 – 9 = -8 (too low)
-1 + 9 = 8 (too high)
3 – 3 = 0 (perfect!)The two numbers you found are 3 and -3. These are the numbers that go into the brackets: (x + 3)(x – 3). 💡
-
-
Question 29 of 36
29. Question
Topic: Factorising Quadratic Expressions.
Please have pen and paper handy to show workings out. 📝
Factorize:
-
⌨️ Type your answer without spaces.
CorrectIncorrectHint
Hint: Finding the Right Numbers When x Coefficient is 0
When the x coefficient is 0, like in x² – 9, write it as x² + 0x – 9 to see it clearly. You need two numbers that multiply to give the end coefficient (-9) and add to give the x coefficient (0). 💡
Step 1: List pairs of numbers that multiply to -9:
1 × -9 = -9
-1 × 9 = -9
3 × -3 = -9Step 2: Check which pair adds up to 0 (the x coefficient):
1 – 9 = -8 (too low)
-1 + 9 = 8 (too high)
3 – 3 = 0 (perfect!)The two numbers you found are 3 and -3. These are the numbers that go into the brackets: (x + 3)(x – 3). 💡
-
-
Question 30 of 36
30. Question
Topic: Factorising Quadratic Expressions.
Please have pen and paper handy to show workings out. 📝
Factorize:
-
⌨️ Type your answer without spaces.
CorrectIncorrectHint
Hint: Finding the Right Numbers
To factorize a quadratic like x² + 5x + 6, you need to find two numbers that multiply to give the end coefficient (6) and add to give the x coefficient (5). 💡
Step 1: List pairs of numbers that multiply to 6:
1 × 6 = 6
2 × 3 = 6
-1 × -6 = 6
-2 × -3 = 6Step 2: Check which pair adds up to 5 (the x coefficient):
1 + 6 = 7 (too high)
2 + 3 = 5 (perfect!)The two numbers you found are 2 and 3. These are the numbers that go into the brackets: (x + 2)(x + 3). If the correct pair were negative, you would still use them, like (x – 2)(x – 3). 💡
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Question 31 of 36
31. Question
Topic: Factorising Quadratic Expressions.
Please have pen and paper handy to show workings out. 📝
Factorize:
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⌨️ Type your answer without spaces.
CorrectIncorrectHint
Hint: Finding the Right Numbers When x Coefficient is 0
When the x coefficient is 0, like in x² – 9, write it as x² + 0x – 9 to see it clearly. You need two numbers that multiply to give the end coefficient (-9) and add to give the x coefficient (0). 💡
Step 1: List pairs of numbers that multiply to -9:
1 × -9 = -9
-1 × 9 = -9
3 × -3 = -9Step 2: Check which pair adds up to 0 (the x coefficient):
1 – 9 = -8 (too low)
-1 + 9 = 8 (too high)
3 – 3 = 0 (perfect!)The two numbers you found are 3 and -3. These are the numbers that go into the brackets: (x + 3)(x – 3). 💡
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Question 32 of 36
32. Question
Topic: Factorising Quadratic Expressions.
Please have pen and paper handy to show workings out. 📝
Factorize:
-
⌨️ Type your answer without spaces.
CorrectIncorrectHint
Hint: Finding the Right Numbers When x Coefficient is 0
When the x coefficient is 0, like in x² – 9, write it as x² + 0x – 9 to see it clearly. You need two numbers that multiply to give the end coefficient (-9) and add to give the x coefficient (0). 💡
Step 1: List pairs of numbers that multiply to -9:
1 × -9 = -9
-1 × 9 = -9
3 × -3 = -9Step 2: Check which pair adds up to 0 (the x coefficient):
1 – 9 = -8 (too low)
-1 + 9 = 8 (too high)
3 – 3 = 0 (perfect!)The two numbers you found are 3 and -3. These are the numbers that go into the brackets: (x + 3)(x – 3). 💡
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Question 33 of 36
33. Question
Topic: Factorising Quadratic Expressions.
Please have pen and paper handy to show workings out. 📝
Factorize:
-
⌨️ Type your answer without spaces.
CorrectIncorrectHint
Hint: Finding the Right Numbers
To factorize a quadratic like x² + 5x + 6, you need to find two numbers that multiply to give the end coefficient (6) and add to give the x coefficient (5). 💡
Step 1: List pairs of numbers that multiply to 6:
1 × 6 = 6
2 × 3 = 6
-1 × -6 = 6
-2 × -3 = 6Step 2: Check which pair adds up to 5 (the x coefficient):
1 + 6 = 7 (too high)
2 + 3 = 5 (perfect!)The two numbers you found are 2 and 3. These are the numbers that go into the brackets: (x + 2)(x + 3). If the correct pair were negative, you would still use them, like (x – 2)(x – 3). 💡
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Question 34 of 36
34. Question
Topic: Factorising Quadratic Expressions.
Please have pen and paper handy to show workings out. 📝
Factorize:
-
⌨️ Type your answer without spaces.
CorrectIncorrectHint
Hint: Finding the Right Numbers When x Coefficient is 0
When the x coefficient is 0, like in x² – 9, write it as x² + 0x – 9 to see it clearly. You need two numbers that multiply to give the end coefficient (-9) and add to give the x coefficient (0). 💡
Step 1: List pairs of numbers that multiply to -9:
1 × -9 = -9
-1 × 9 = -9
3 × -3 = -9Step 2: Check which pair adds up to 0 (the x coefficient):
1 – 9 = -8 (too low)
-1 + 9 = 8 (too high)
3 – 3 = 0 (perfect!)The two numbers you found are 3 and -3. These are the numbers that go into the brackets: (x + 3)(x – 3). 💡
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Question 35 of 36
35. Question
Topic: Factorising Quadratic Expressions.
Please have pen and paper handy to show workings out. 📝
Factorize:
-
⌨️ Type your answer without spaces.
CorrectIncorrectHint
Hint: Finding the Right Numbers
To factorize a quadratic like x² + 5x + 6, you need to find two numbers that multiply to give the end coefficient (6) and add to give the x coefficient (5). 💡
Step 1: List pairs of numbers that multiply to 6:
1 × 6 = 6
2 × 3 = 6
-1 × -6 = 6
-2 × -3 = 6Step 2: Check which pair adds up to 5 (the x coefficient):
1 + 6 = 7 (too high)
2 + 3 = 5 (perfect!)The two numbers you found are 2 and 3. These are the numbers that go into the brackets: (x + 2)(x + 3). If the correct pair were negative, you would still use them, like (x – 2)(x – 3). 💡
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Question 36 of 36
36. Question
Topic: Factorising Quadratic Expressions.
Please have pen and paper handy to show workings out. 📝
Factorize:
-
⌨️ Type your answer without spaces.
CorrectIncorrectHint
Hint: Finding the Right Numbers When x Coefficient is 0
When the x coefficient is 0, like in x² – 9, write it as x² + 0x – 9 to see it clearly. You need two numbers that multiply to give the end coefficient (-9) and add to give the x coefficient (0). 💡
Step 1: List pairs of numbers that multiply to -9:
1 × -9 = -9
-1 × 9 = -9
3 × -3 = -9Step 2: Check which pair adds up to 0 (the x coefficient):
1 – 9 = -8 (too low)
-1 + 9 = 8 (too high)
3 – 3 = 0 (perfect!)The two numbers you found are 3 and -3. These are the numbers that go into the brackets: (x + 3)(x – 3). 💡
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